In figure, find all the four angles of the cyclic quadrilateral ABCD.

We know that the pair of opposite angles of a cyclic quadrilateral is supplementary i.e. sum is 180°.
Firstly, 2x° + 3x° = 180°
⇒ 5x° = 180°
⇒x° = 180°/ 5
∴ x° = 36°
Also, y° + 2y° = 180°
⇒ 3y° = 180°
⇒y° = 180°/ 3
∴ y° = 60°
Now,
∴ ∠A = y° = 60°
∴ ∠B = 3x° = 3 (36°) = 108°
∴ ∠C = 2y° = 2 (60°) = 120°
∴ ∠D = 2x° = 2 (36°) = 72°
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