In a frequency distribution table, the mid - point of a class is 10 and the class size of each class is 6; the lower limit of the class is
Let the upper limit of the class is u
And lower limit of the class is l
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_______(i)
Also class size = upper classs boundary – lower class boundary
6 = u – l______(ii)
From (i) and (ii), u = 13 and l = 7
So, upper class boundary = 13 and lower class boundary = 7
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