Q9 of 35 Page 195

In a continuous frequency distribution table, if the mid - point of a class is 42 and class size is 10, then let us write the upper and lower limit of the class.

given mid - point = 42

Class size = 10


Let lower class boundary = L


mid value of class interval


_____(i)


class size = upper class boundary - lower class boundary


⇒10 = u - L______(ii)


Solving equation (i) and (ii), we get


u = 47 and L = 37


So lower class boundary = 37 and upper class boundary = 47


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