Q31 of 75 Page 81

Calculate the mass of each of the following:

5 moles of aluminium borate

Given: Number of moles = 5


Atomic mass of AlBO3 = 30+ 10.8 + 2 × 16 = 72.8g/mol


To find out the mass of aluminium borate, apply the formula given:



⇒


⇒ Mass = 5 mol × 72.8g/mol


⇒ Mass = 364g


Thus, the mass of aluminium borate is 364g.


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29

Give the formulae of the compounds formed from the following set of elements.

(i) Carbon and hydrogen


(ii) Nitrogen and magnesium


(iii) Sodium and phosphorus


(iv) Potassium and oxygen


(v) Boron and oxygen

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In an experiment, 1.288 g of barium sulphate was obtained from 1.03 g of barium. In another experiment, 3.672 g of barium sulphate gave, on reduction, 2.938 g of barium. Show that these figures verify the law of constant proportions.

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Calculate the mass of each of the following:

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