A takes 6 days less than B to do a work. If both A and B working together can do it in 4 days how many days will B take to finish it?
We call the time it takes for B to finish the piece of work x.
For problems like these, we must consider how much work can be done in one day.
Work done by B in 1 day = 1/x
Work done by A in 1 day = 1/(x – 6)



4(2x – 6) = x(x – 6)
8x – 24 = x2 – 6x
x2 – 14x + 24 = 0
(x – 12)(x – 2) = 0
⇒ x = 12 or x = 2
∴ If the time it takes B is 2 days, then the time it takes A is −4 days, which has no sense.
Therefore, it would take B a period of 12 days to finish the job.
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