Show that the sum of the three vectors determined by the medians of a triangle directed from the vertices is zero.
Consider a ΔABC with D, E and F being the midpoints of sides BC, CA and AB respectively.
Let the position vectors of these vertices and midpoints be as shown in the figure.
We need to prove
.

As D is the midpoint of BC, using midpoint formula, we have
![]()
Similarly,
and
.
Recall the vector
is given by
![]()
![]()
Similarly,
and ![]()
Now, consider the vector
.
![]()
But
,
and![]()


![]()
![]()
![]()
Thus, the sum of the three vectors determined by the medians of a triangle is zero.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
