Five forces and
and
act at the vertex of a regular hexagon ABCDEF. Prove that the resultant is 6
where O is the centre of hexagon.
Given a regular hexagon ABCDEF with O as the centre of the hexagon as shown in figure below

To prove ![]()
We know that centre O of the hexagon bisects the diagonals
∴,
, ![]()
Consider ΔABO and apply triangle law of vector, we get
![]()
And consider ΔACO and apply triangle law of vector, we get
![]()
And consider ΔAEO and apply triangle law of vector, we get
![]()
And consider ΔAFO and apply triangle law of vector, we get
![]()
Now,
![]()
Substitute the corresponding values from eqn(i) to eqn(v) in above eqn, we get
![]()
[from eqn(i)]
[as
and
]
![]()
![]()
Hence ![]()
Therefore the resultant of the five forces
and
is ![]()
Hence proved
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