Prove that a necessary and sufficient condition for three vectors
and
to be coplanar is that there exist scalars
not all zero simultaneously such that ![]()
Given: The vectors
,
and
.
To Prove: (a). Necessary condition: The vectors
,
and
will be coplanar if there exist scalar l, m, n not all zero simultaneously such that
.
(b). Sufficient condition: For vectors
,
and
, there exist scalar l, m, n not all zero simultaneously such that ![]()
Proof:
(a). Necessary condition: Let
,
and
are three coplanar vectors.
Then, one of them can be expressed as a linear combination of the other two.
Then, let ![]()
Rearranging them we get,
![]()
Here, let
x = l
y = m
–1 = n
We have,
![]()
Thus, if
,
and
are coplanars, there exists scalar l, m and n (not all zero simultaneously zero) such that
.
∴ necessary condition is proved.
(b). Sufficient condition: Let
,
and
be three vectors such that there exists scalars l, m and n not all simultaneously zero such that
.
![]()
![]()
Now, divide by n on both sides, we get
![]()
![]()
Here, we can see that
is the linear combination of
and
.
⇒ Clearly,
,
and
are coplanar.
∴ sufficient condition is also proved.
Hence, proved.
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