If
are non–zero, non-coplanar vectors, prove that the following vectors are coplanar :
and ![]()
We have been given that,
,
and
.
We can form a relation using these three vectors. Say,
![]()
![]()
![]()
Compare the vectors
,
and
. We get
1 = – 2y …(1)
–2 = –3x + 3y …(2)
3 = 5x – 4y …(3)
Solving equation (1) for y,
Equation (1), –2y = 1
![]()
Put
in equation (2), we get
![]()
![]()
![]()
⇒ –6x – 3 = –2 × 2
⇒ –6x – 3 = –4
⇒ –6x = –4 + 3
⇒ –6x = –1
![]()
Substituting
and
in equation (3), we get
3 = 5x – 4y
Or 5x – 4y = 3
![]()
![]()
![]()
![]()
![]()
But ![]()
∵, L.H.S ≠ R.H.S
⇒ The value of x and y doesn’t satisfy equation (3).
Thus,
,
and
are not coplanar.
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