If
are two non-collinear vectors, prove that the points with position vectors
and
are collinear for all real values of ![]()
Let us understand that, two more points are said to be collinear if they all lie on a single straight line.
Given that,
and
are two non-collinear vectors.
Let the points be A, B and C having position vectors such that,
![]()
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So, in this case if we prove that
and
are parallel to each other, then we can easily show that A, B and C are collinear.
Therefore,
is given by
![]()
![]()
![]()
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…(i)
And
is given by
![]()
![]()
![]()
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Let us note the relation between
and
.
We know, ![]()
Or ![]()
Or
[∵, from (i)]
Or
…(ii)
If λ is any real value, then
is also a real value.
Then, for any real value
, we can write
![]()
From (ii) equation, we can write
![]()
This relation shows that
and
are parallel to each other.
But also,
is the common vector in
and
.
⇒
and
are not parallel but lies on a straight line.
Thus, A, B and C are collinear.
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