A voltage V = V0 sin ωt is applied to a series LCR circuit. Derive the expression for the average power dissipated over a cycle. Under what condition:
(i) no power is dissipated even though the current flows through the circuit,
(ii) maximum power is dissipated in the circuit?

The voltage given is, V = V0 sin ωt
The net impedance of the circuit is,
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The current in the circuit is,
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Where,
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So, the instantaneous power can be written as,
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Using the trigonometric identity,
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We get,
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So, average power is,

The above integral evaluates to,
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Case 1:
For a pure inductive circuit or pure capacitive circuit, the phase difference between the current and voltage, Φ=ϖ/2
So, ![]()
The power dissipated is Zero
Case 2:
For power dissipated at resonance in an LCR circuit.
Xc-Xl=0, Φ=0
Cos Φ=1
So, Maximum power is dissipated by the resistance.
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