An electron microscope uses electrons accelerated by a voltage of 50 kV. Determine the de-Broglie wavelength associated with the electrons. Taking other factors, such as numerical aperture etc. to be same, how does the resolving power of an electron microscope compare with that of an optical microscope which used yellow light?
Given: -
The voltage used for acceleration, 50 kV
Formula: -
The de -broglie wavelength is given as,
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Where,
is the de -broglie wavelength, h is planck’s constant, KE is the kinetic energy of the particle, m is the mass of the particle,
Calculations: -
Substituting the values in the formula we get,
![]()
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Conclusion: -
The de-Broglie wavelength of the electron is 5.4 × 10-12 m.
We know that the resolving power is inversely proportional to the wavelength of the radiation used whether it be light or any particle like electrons,
Resolving power![]()
So,
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This shows that the resolving power of an electron microscope is 105 times than the resolving power of the electron microscope using yellow light of wavelength 590 nm.
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