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8. Permutations
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Q2 of 140 Page 267

Prove that LCM {6!, 7!, 8!} = 8!

To Prove : LCM {6!, 7!, 8!} = 8!


Formula :


LCM is the smallest possible number that is a multiple of two or more numbers.


Here, we observe that (8!) is the first number which is a multiple of all three given numbers i.e. 6!, 7! and 8!.





Therefore, 8! is the LCM of {6!, 7!, 8!}


Conclusion : Hence proved


More from this chapter

All 140 →
1

Compute:

(i)


(ii)


(iii)


3

Prove that .

4

If , find the value of x.

5

Write the following products in factorial notation:

(i) 6 × 7 × 8 × 9 × 10 × 11 × 12


(ii) 3 × 6 × 9 × 12 × 15


Questions · 140
8. Permutations
1 2 3 4 5 6 7 8 9 10 11 12 13 14 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 1 1 1 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 1 2 3 4 5 6 7 1 2 3 4 5 6 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
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