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8. Permutations
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Q19 of 140 Page 307

How many 6 - digit numbers can be formed by using the digits 4, 5, 0, 3, 4, 5?

To find: number of 6 digit


0 cannot be in the first place because that would make a 5 - digit number


Total number of 6 - digit numbers = Total number of number possible - Number of numbers with 0 at the first place


Total number of numbers possible =


Number of numbers with 0 at first place =


Number of 6 - digit numbers = 180 - 30 = 150


150 six - digit numbers are possible


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17

How many numbers can be formed with the digits 2, 3, 4, 5, 4, 3, 2 so that the odd digits occupy the odd places?

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How many 7 - digit numbers can be formed by using the digits 1, 2, 0, 2, 4, 2, 4?

20

The letters of the word ‘INDIA’ are arranged as in a dictionary. What are the 1st, 13th, 49th and 60th words?

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Questions · 140
8. Permutations
1 2 3 4 5 6 7 8 9 10 11 12 13 14 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 1 1 1 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 1 2 3 4 5 6 7 1 2 3 4 5 6 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
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