Evaluate:
6P6
To find: the value of 6P6
Formula Used:
Total number of ways in which n objects can be arranged in r places (Such that no object is replaced) is given by,
nPr![]()
Therefore,
6P6![]()
62P3 = 6 × 5 × 4 × 3 × 2× 1= 720
Thus, the value of 6P6 is 720.
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