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8. Permutations
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Q1 of 140 Page 288

Evaluate:

9P0


To find: the value of 9P0


Formula Used:


Total number of ways in which n objects can be arranged in r places (Such that no object is replaced) is given by,


nPr


Therefore,


9P0


9P0 = 1


Thus, the value of 9P0 is 1.


More from this chapter

All 140 →
1

Evaluate:

62P3


1

Evaluate:

6P6


2

Prove that 9P3 + 3 × 9P2 = 10P3.

3

(i) If nP5 = 20 × nP3, find n.

(ii) If 16 × nP3 = 13 × n+1P3, find n.


(iii) If 2nP3 = 100 × nP2, find n.


Questions · 140
8. Permutations
1 2 3 4 5 6 7 8 9 10 11 12 13 14 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 1 1 1 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 1 2 3 4 5 6 7 1 2 3 4 5 6 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
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