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8. Permutations
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Q13 of 140 Page 267

Prove that (n + 2) × (n!) + (n + 1) ! = (n!). (2n + 3)

To Prove :


Formula :


L.H.S. = (n + 2) × (n!) + (n + 1)!


= (n + 2) × (n!) + (n + 1) × (n!)


= (n!) × [(n + 2) + (n + 1)]


= (n!) × (2n + 3)


= R.H.S.


∴L.H.S. = R.H.S.


Conclusion : (n + 2) × (n!) + (n + 1)! = (n!) × (2n + 3)


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Questions · 140
8. Permutations
1 2 3 4 5 6 7 8 9 10 11 12 13 14 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 1 1 1 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 1 2 3 4 5 6 7 1 2 3 4 5 6 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
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