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8. Permutations
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Q8 of 140 Page 288

Find n, If n+5Pn+1 = (n – 1). n+3Pn, find n.

To find: the value of n


Formula Used:


Total number of ways in which n objects can be arranged in r places (Such that no object is replaced) is given by,


nPr


n+5Pn+1 = (n – 1). n+3Pn







(n - 7)(n - 6) = 0


n = 7, 6


Hence, values of n are 7 & 6


More from this chapter

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6

If 15Pr–1 : 16Pr–2, = 3 : 4, find r.

7

If 2n–1Pn : 2n+1Pn–1, = 22 : 7, find n.

9

Prove that 1 + 1. 1P1 + 2. 2P2 + 3. 3P3 + …. n. nPn = n+1Pn+1.

10

Find the number of permutations of 10 objects, taken 4 at a time.

Questions · 140
8. Permutations
1 2 3 4 5 6 7 8 9 10 11 12 13 14 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 1 1 1 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 1 2 3 4 5 6 7 1 2 3 4 5 6 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
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