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8. Permutations
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Q11 of 140 Page 267

If = 44 : 3, find the value of n.

Given Equation :



To Find : Value of n


Formula :


By given equation,





By using above formula,



Cancelling terms (n - 2)! , (2!), (2n - 3)! & n, we get,



….. taking 2 common from the term (2n - 2)



∴ (2n - 1) = 11


∴n = 6


Conclusion : Value of n is 6.


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9

If (n + 3) ! = 56 × (n + 1) !, find the value of n.

10

If = 2 : 1, find the value of n.

12

Evaluate , when n = 15 and r = 12.

13

Prove that (n + 2) × (n!) + (n + 1) ! = (n!). (2n + 3)

Questions · 140
8. Permutations
1 2 3 4 5 6 7 8 9 10 11 12 13 14 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 1 1 1 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 1 2 3 4 5 6 7 1 2 3 4 5 6 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
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