Q1 D of 52 Page 125

I/we factorise the following algebraic expressions:

y2 + 23y + 102


An algebraic expression is an expression built up from integer constants, variables, and the algebraic operations.

And, factorization or factoring consists of writing a number or another mathematical object as a product of several factors, usually smaller or simpler objects of the same kind.


Let’s factorize the given algebraic expression.


We have y2 + 23y + 102.


First: Multiply the coefficient of y2 and the constant.


Coefficient of y2 = 1


Constant = 102


1 × 102 = 102 …(a)


Now, Observe the coefficient of y = 23


We need to split the value obtained at (a), such that the sum/difference of the split numbers comes out to be 23.


To split: We need to find the factors of 102.


Factors of 102 = 2 × 3 × 17


Add 17 and (2 × 3 =) 6 = 17 + 6 = 23


Multiply 17 and 6 = 17 × 6 = 102


Since, the sum of 17 and 6 is 23 and multiplication is 102. So, we can write


y2 + 23y + 102 = y2 + (17y + 6y) + 102


y2 + 23y + 102 = y2 + 17y + 6y + 102


y2 + 23y + 102 = (y2 + 17y) + (6y + 102)


Now, take out common number or variable in first two pairs and the last two pairs subsequently.


y2 + 23y + 102 = y(y + 17) + 6(y + 17)


Now, take out the common number or variable again from the two pairs.


y2 + 23y + 102 = (y + 17)(y + 6)


Thus, the factorization of y2 + 23y + 102 = (y + 17)(y + 6).


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