Let’s resolve into factors:
x2 + 2ax + (a + b)(a-b)
x2 + 2ax + (a + b)(a-b)
=x2 + (a + b)x + (a-b)x + (a + b)(a-b)
=x(x + a + b) + (a-b)(x + a + b)
=(x + a-b)(x + a + b)
∴ the factors of x2 + 2ax + (a + b)(a-b) are (x + a-b)(x + a + b)
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