Q1 L of 52 Page 131

Let’s resolve into factors:

2a6-13a3-24


2a6-13a3-24

=2a6-16a3 + 3a3-24


=2a3(a3-8) + 3(a3-8)


= (2a3 + 3) (a3-8)


Apply the formula a3 - b3 = (a - b)(a2 + ab + b2) in (a3-8),


(a3-8) = (a3-23)


= (a-2)(a2 + 4 + 2a)


So,


2a6-13a3-24= (2a3 + 3) (a-2)(a2 + 4 + 2a)


∴ the factors of 2a6-13a3-24 are (2a3 + 3) (a-2)(a2 + 4 + 2a).


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