Q1 of 52 Page 131

Let’s resolve into factors:

8a4 + 2a2-45


8a4 + 2a2-45


=8a4 + 20a2- 18a2-45


=4a2(2a2 + 5)-9(2a2 + 5)


=(4a2-9)(2a2 + 5)


Apply the formula a2 – b2 = (a-b) (a+b) in(4a2-9)


(4a2-9)= ((2a)2 – 32)


= (2a-3)(2a+3)


So,


8a4 + 2a2-45 = (2a2 + 5) (2a-3)(2a+3)


∴ the factors of 8a4 + 2a2-45 are (2a2 + 5) (2a-3)(2a+3)


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