Q2 B of 52 Page 131

Let’s resolve the following algebraic expressions into factors by expressing them as the difference of two squares:

x2 + 5x + 6


Add and subtract the half of square of coefficient of x.







Apply the formula a2 – b2 = (a + b)(a-b)





= (x + 2)(x + 3)


Hence the factors of x2 + 5x + 6 is (x + 2)(x + 3).


More from this chapter

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1

Let’s resolve into factors:

6(a + b)2 + 5(a2-b2)-6(a-b)2


 2 A

Let’s resolve the following algebraic expressions into factors by expressing them as the difference of two squares:

x2-2x-3


 2 C

Let’s resolve the following algebraic expressions into factors by expressing them as the difference of two squares:

3x2-7x-6


 2

Let’s resolve the following algebraic expressions into factors by expressing them as the difference of two squares:

3a2-2a-5