Q1 of 52 Page 131

Let’s resolve into factors:

3(a + b)2-2a-2b-8


3(a + b)2-2a-2b-8


=3(a + b)2-2(a + b)-8


=3(a + b)2-6(a + b) + 4(a + b)-8


=3(a + b){a + b-2} + 4(a + b-2)


=(3a + 3b + 4)(a + b-2)


∴ the factors of 3(a + b)2-2a-2b-8 are (3a + 3b + 4)(a + b-2)


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