Q2 C of 52 Page 131

Let’s resolve the following algebraic expressions into factors by expressing them as the difference of two squares:

3x2-7x-6


make the coefficient of x2 as 1.



Add and subtract the half of square of coefficient of x.







Apply the formula a2 – b2 = (a + b)(a-b)






= (x-3)(3x + 2)


Hence the factors of 3x2-7x-6 are (x-3)(3x + 2).


More from this chapter

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2 A

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x2-2x-3


 2 B

Let’s resolve the following algebraic expressions into factors by expressing them as the difference of two squares:

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Let’s resolve the following algebraic expressions into factors by expressing them as the difference of two squares:

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ax2 + (a2 + 1)x + a