(a) Using valence bond theory, write the hybridisation and magnetic character of the complex [Fe(CN)6]4-. (Atomic no. of Fe = 26)
(b) Write the electronic configuration of d6 on the basis of crystal field theory when
(i) Δo< P and
(ii) Δo > P
(a) Fe exists in +2 oxidation state in [Fe(CN)6]4-.
Electronic configuration of Fe+2 = 3d6

As CN is a strong field ligand, there will be pairing of electrons in d orbital.

Hybridization and shape of [Fe(CN)6]4- is d2sp3 and octahedral respectively.
Since, there is no unpaired electron present therefore, the complex is diamagnetic in nature.
(b) (i) When Δo< P, the electronic configuration of d6 will be t2g3eg3.
(ii) When Δo > P, the electronic configuration of d6 will be t2g6eg0.
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