E° for the given redox reaction is 2.71 V
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Calculate Ecell for the reaction. Write the direction of flow of current when an external opposite potential applied is
(i) Less than 2.71 V and
(ii) Greater than 2.71 V
OR
(a) A steady current of 2 A was passed through two electrolytic cells X and Y connected in series containing electrolytes FeSO4 and FeSO4 until 2.8 g of Fe deposited at the cathode of cell X. how long did the current flow? Calculate the mass of Zn deposited at the cathode of cell Y.
(b) In the plot of molar conductivity (Λm) v/s square root of concentration (c1/2), following curve is obtained for two electrolytes A and B:

Answer the following:
(i) Predict the nature of electrolytes A and B
(ii) What happens on extrapolation of Λm to concentration approaching zero for electrolytes A and B?
Given:
E° = 2.71 V
Solution:
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For the given reaction the Nernst equation is written as,

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For the given conditions,
(i) Ecell > 2.71 V, the current flows from cathode to anode (conventional direction)
(ii) Ecell < 2.71 V, i.e. the external voltage is greater than the emf of the cell, the direction of the flow is from anode to cathode (direction is reversed)
OR
(i) As the conductivity is linearly dependent on the square root of concentration the line on Λ v/s c1/2 suggests that A is a strong electrolyte.
When initially when the concentration is increases the conductivity drops rapidly but after certain point there are enough ions and no more addition of B will decrease the conductivity significantly, thus B is a weak electrolyte.
(ii) Extrapolation of values of Λm gives the maximum values of conductivity i.e. Λ°m for strong electrolytes at zero concentration. This cannot be found for Weak electrolytes as the relation is non-linear curvature which does not meet the conductivity.
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