Q10 of 149 Page 194

A uniform rod is kept vertically on a horizontal smooth surface at a point O. If it is rotated slightly and released, it falls down on the horizontal surface. The lower end will remain

The rod is uniform and the length is l. So, the center of mass is at l/2 distance. The equation of motion,



As, the force on center of mass is in –j direction, it falls directly on the point O. Hence, the end is at a distance l/2.

More from this chapter

All 149 →
8

Let be a force acting on a particle having position vector Let be the torque of this force about the origin, then

 9

One end of a uniform rod of mass m and length l is clamped. The rod lies on a smooth horizontal surface and rotates on it about the clamped end at a uniform angular velocity ω. The force exerted by the clamp on the rod has a horizontal component

 11

A circular disc A of radius r is made from an iron plate of thickness t and another circular disc B of radius 4r is made from an iron plate of thickness t/4. The relation between the moments of inertia IA and IB is

 12

Equal torques act on the discs A and B of the previous problem, initially both being at rest. At a later instant, the linear speeds of a point on the rim of A and another point on the rim of B are and respectively. We have