Two particles of masses m1 and m2 are joined by a light rigid rod of length r. The system rotates at an angular speed ω about an axis through the centre of mass of the system and perpendicular to the rod. Show that the angular momentum of the system is L = μ r2 ω where μ is the reduced mass of the system defined as

The average momentum of the mass
when at the middle of the system is denoted as ![]()
The average momentum is written as
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And likewise, the angular momentum of mass
is
![]()
Hence adding both the average momentum we get the net average momentum as
![]()
(The value of
is denoted by
)
Therefore, the net average momentum ![]()
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