A uniform meter stick of mass 200 g is suspended from the ceiling through two vertical strings of equal lengths fixed at the ends. A small object of mass 20 g is placed on the stick at a distance of 70 cm from the left end. Find the tensions in the two strings.
The value of tension 
, 
Given
The uniform meter stick of mass is given as 200, the mass of 200g is at a distance of 50 cm and 20g is suspended at a distance of 30cm
Formula Used
The torque applied by the mass and radius of the rod is the product of the force and the radius of rotation of the rod
where
is the torque of the rod, F is the force in terms of tension, r is the length of the weight suspended at certain distance.
Explanation
The value of the tension given are 
and
The total tension formed due to the suspended weights are given as
The rod is kept at an equilibrium when the rod is at rest
Placing the equation (1) in equation (2) we get the value of
Putting the value of 
, in equation 2, we get the value of 
as
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