Write the equations when
(i) Ethyl Chloride is treated with alcoholic KOH.
(ii) Chlorobenzene is treated with CH3Cl in presence of anhydrous AlCl3.
(i) Ethyl Chloride is subjected to substitution and displacement reactions with alkali KOH and it forms a product of Ethyl Alcohol.
(ii) this reaction is Friedel crafts alkylation. AlCl3 is a Lewis acid and readily accepts Cl- from CH3Cl and gives an electrophile CH3+ which undergoes electrophilic substitution reaction with chlorobenzene.
Chlorobenzene gives 4-chloro toluene and 2-chloro toluene.
+ AlCl3 + CH3Cl →
+ 
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