Q9 of 186 Page 229

In the given figure, ABC is a triangle and PQ is a straight line meeting AB in P and AC in Q. If AP = 1 cm, PB = 3 cm, AQ = 1.5 cm, QC = 4.5 cm, prove that area of ΔAPQ is 1/16 of the area of ΔABC.

We have



Also ∠ A = ∠ A


So, by SAS similarity criterion ΔAPQ ~ ΔABC


We know that if two triangles are similar then the ratio of their areas is equal to the ratio of the squares of their corresponding sides.




Hence, proved.


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