Match the following columns:

Column I	Column II
A. In a given ΔABC, DE || BC and . If AC = 5.6 cm then AE = ………. cm.	P. 6
B. If ΔABC ~ ΔDEF such that 2AB = 3DE and BC = 6 cm then EF = ……….. cm.	Q. 4
C. If ΔABC ~ ΔPQR such that ar(ΔABC) : ar(ΔPQR) = 9 :16 and BC = 4.5 cm then QR = cm.	R. 3
D. In the given figure, AB || CD and OA = (2x + 4) cm, OB = (9x — 21) cm, OC = (2x —1) cm and OD = 3 cm. Then x = ?	S. 2.1

A)

Given that DE||BC,
by B.P.T.,

Let AE = x

Then, from the figure, EC = 5.6-x

5x = 3(5.6-x)

5x = 16.8-3x

8x = 16.8

x = 2.1cm

Therefore, (A)-(s)

B)
As Δ ABCΔDEF,

3EF = 2BC

3EF = 2 × 6

EF = 4cm

Therefore,(B)-(q)

C)

QR =
QR = = 6cm

Therefore (C)-(p)

D)

(BPT)

⇒ 3(2x + 4) = (2x-1)(9x-21)

⇒ 6x + 12 = 18x²-42x-9x + 21

⇒ 18x²-57x + 9 = 0

⇒18x2-54x-3x + 9 = 0

⇒ 18x(x-3)-3(x-3) = 0

⇒ (18x-3)(x-3) = 0

So, x = 3 or x =

But for x = , 2x-1<0 which is not possible.
Therefore, (D)-(r)