Q29 of 186 Page 263

In ΔABC, it is given that AB = 9 cm, BC = 6 cm and CA = 7.5 cm. Also, ΔDEF is given such that EF = 8 cm and ΔDEF ~ ΔABC. Then, perimeter of ΔDEF is

Perimeter of Δ ABC = AB + BC + CA


= 9 + 6 + 7.5


= 22.5 cm


Since the Δ ABC ∼ DEF


= (ratio of perimeter of triangles is equal to the ratio of the sides of the triangle )


=


=


= 30 cm

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