Q16 of 186 Page 263

In a rhombus of side 10 cm, one of the diagonals is 12 cm long. The length of the second diagonal is

Since the diagonals of the rhombus bisects each other at 90°

∴ DO = OB = 6 cm

∠ AOD = ∠ DOC = ∠ COB = ∠BOA = 90°

Δ AOD is right angled Δ with

AD = 10 cm (given)

OD = 6 cm

∠ AOD = 90°

So DA = 10 = hypotenuse

(DA)² = (DO)² + (AO)²

100 – 36 = (AO)²

8 = AO

∴ AC = 16

In a triangle, the perpendicular from the vertex to the base bisects the base. The triangle is

In an equilateral triangle ABC, if AD ⊥ BC then which of the following is true?

The lengths of the diagonals of a rhombus are 24 cm and 10 cm. The length of each side of the rhombus is

If the diagonals of a quadrilateral divide each other proportionally then it is a