Q39 of 186 Page 263

In the given figure, two line segments AC and BD intersect each other at the Point P such that PA = 6 cm, PB = 3 cm, PC = 2.5 cm, PD = 5 cm, ∠APB = 50° and ∠CDP = 30° then ∠PBA = ?

In ΔAPB and Δ DPC,
∠APB = ∠DPC = 50°


By SAS property, Δ APBDPC
∠PBA = ∠DPC
In Δ DPC,
∠D + ∠ P + ∠C = 180°


∠ C = 100°
 ∴ ∠PBA = ∠DPC = 100°

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