In ΔABC, AB = 6√3 cm, AC = 12 cm and BC = 6 cm. Then, ∠B is
AB = 6√3cm.
In ΔABC,
AB2 + BC2 = AC2![]()
Since the square of the longest side is equal to the sum of the squares of the remaining two sides of Δ ABC. Therefore ABC is right angled at B.
∠ B = 90°
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