Attempt of the following sub questions:
Find the eighteenth term of the A.P.:1, 7, 13, 19, …
Given: A.P 1, 7, 13, 19…
nth term of A.P is given by tn = a + (n – 1) × d
where,
a = first term of A.P = 1
d = common difference = 7 – 1 = 6
we have to find the 18th term hence n = 18
⇒ t18 = 1 + (18 – 1) × 6
⇒ t18 = 1 + 17 × 6
⇒ t18 = 1 + 102
⇒ t18 = 103
Therefore 18th term of the A.P 1, 7, 13, 19… is 103
Couldn't generate an explanation.
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