Attempt of the following sub questions:
Solve the following quadratic equation by using formula method:
7y2 – 5y – 2 = 0
Given: 7y2 – 5y – 2 = 0
Compare equation with ax2 + bx + c = 0 we get
a = 7, b = -5 and c = -2
Formula: y = ![]()
⇒ y =
⇒ y = ![]()
⇒ y = ![]()
⇒ y = ![]()
⇒ y =
and y = ![]()
∴ y = 1 and y = ![]()
Couldn't generate an explanation.
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