Which of the following sequences are A.P. ? If they are A.P. find the common difference.
127, 132, 137, . . .
127, 132, 137, . . .
Here, the first term, a1 = 127
Second term, a2 = 132
a3 = 137
Now, common difference = a2 – a1 = 132 – 127 = 5
Also, a3 – a2 = 137 – 132 = 5
Since, the common difference is same.
Hence the terms are in Arithmetic progression with common difference, d = 5.
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