Q3 of 69 Page 66

Given Arithmetic Progression 12, 16, 20, 24, . . . Find the 24th term of this progression.

Given A.P. is 12, 16, 20, 24, . . .


Where first term a = 12


Second term t1 = 16


Third term t2 = 20


Common Difference d = t2 – t1 = 20 – 16 = 4


We know that, nth term of an A.P. is


tn = a + (n – 1)d


We need to find the 24th term,


Here n = 24


Thus, t24 = 12 + (24 – 1)× 4


t24 = 12 + (23)× 4 = 12 + 92 = 104


Thus, t24 = 104


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