Q6 of 69 Page 72

Sum of first 55 terms in an A.P. is 3300, find its 28th term.

Given: S55 = 3300 where n = 55

Now, By using sum of nth term of an A.P. we will find it’s sum



Where, n = no. of terms


a = first term


d = common difference


Sn = sum of n terms


Thus, on substituting the given value in formula we get,





3300 = 55 × [ a + 27d]



a + 27d = 60 ……(1)


We need to find value of 28th term i.e t28


Now, By using nth term of an A.P. formula


tn = a + (n – 1)d


where n = no. of terms


a = first term


d = common difference


tn = nth terms


we can find value of t28 by substituting all the value in formula we get,


t28 = a + (28 – 1) d


t28 = a + 27 d


From eq. (1) we get,


t28 = a + 27 d = 60


t28 = 60


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