Q4 of 69 Page 66

Find the 19th term of the following A.P.

7, 13, 19, 25, . . .

Given A.P. is 7, 13, 19, 25, . . .

Where first term a = 7


Second term t1 = 13


Third term t2 = 19


Common Difference d = t2 – t1 = 19 – 13 = 6


We know that, nth term of an A.P. is


tn = a + (n – 1)d


We need to find the 19th term,


Here n = 19


Thus, t19 = 7 + (19 – 1)× 6


t19 = 7 + (18)× 6 = 7 + 108 = 115


Thus, t19 = 115


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