11, 8, 5, 2, . . . In this A.P. which term is number – 151?

By, given A.P. 11, 8, 5, 2, . . .

we know that

a = 11, t₁ = 8, t₂ = 5

Thus, d = t₂ – t₁ = 5 – 8 = – 3

Given: t_n = – 151

Now, By using n^th term of an A.P. formula

t_n = a + (n – 1)d

we can find value of “n”

Thus, on substituting all the value in formula we get,

– 151 = 11 + (n – 1)× ( – 3)

⇒ – 151 – 11 = (n – 1)× ( – 3)

⇒ – 162 = (n – 1) × ( – 3)

⇒ n = 54 + 1 = 55