Q2 of 69 Page 66

Decide whether following sequence is an A.P., if so find the 20th term of the progression.

– 12, – 5, 2, 9, 16, 23, 30, . . .

Given A.P. is – 12, – 5, 2, 9, 16, 23, 30, . . .


Where first term a = – 12


Second term t1 = – 5


Third term t2 = 2


Common Difference d = t2 – t1 = 2 – ( – 5) = 2 + 5 = 7


We know that, nth term of an A.P. is


tn = a + (n – 1)d


We need to find the 20th term,


Here n = 20


Thus, t20 = – 12 + (20 – 1)× 7


t20 = – 12 + (19)× 7 = – 12 + 133 = 121


Thus, t20 = 121


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