Decide whether following sequence is an A.P., if so find the 20th term of the progression.
– 12, – 5, 2, 9, 16, 23, 30, . . .
Given A.P. is – 12, – 5, 2, 9, 16, 23, 30, . . .
Where first term a = – 12
Second term t1 = – 5
Third term t2 = 2
Common Difference d = t2 – t1 = 2 – ( – 5) = 2 + 5 = 7
We know that, nth term of an A.P. is
tn = a + (n – 1)d
We need to find the 20th term,
Here n = 20
Thus, t20 = – 12 + (20 – 1)× 7
t20 = – 12 + (19)× 7 = – 12 + 133 = 121
Thus, t20 = 121
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