Find the 27th term of the following A.P.

9, 4, – 1, – 6, – 11, . . .

Given A.P. is 9, 4, – 1, – 6, – 11, . . .

Where first term a = 9

Second term t₁ = 4

Third term t₂ = – 1

Common Difference d = t₂ – t₁ = – 1 – 4 = – 5

We know that, n^th term of an A.P. is

t_n = a + (n – 1)d

We need to find the 27^th term,

Here n = 27

Thus, t₂₇ = 9 + (27 – 1)× ( – 5)

t₂₇ = 9 + (26)× ( – 5) = 9 – 130 = – 121

Thus, t₂₇ = – 121