Carry out the following divisions48a3 by 6a

In the given termDividend = 48a3 = 2 × 2 × 2 × 2 × 3 × a × a × aDivisor = 6a = 2 × 3 × a= 2 × 2 × 2 × a × a= 8a2Hence dividing 48a3 by 6a gives 8a2

Q1 of 105 Page 279

Carry out the following divisions
48a³ by 6a

In the given term

Dividend = 48a³ = 2 × 2 × 2 × 2 × 3 × a × a × a

Divisor = 6a = 2 × 3 × a

= 2 × 2 × 2 × a × a

= 8a²

Hence dividing 48a³ by 6a gives 8a²

The lengths of the sides of a triangle are integrals, and its area is also integer. One side is 21 and the perimeter is 48. Find the shortest side.

Find the values of ‘m’ for which x² + 3xy + x + my –m has two linear factors in x and y, with integer coefficients.

Carry out the following divisions

14x³ by 42x²

Carry out the following divisions

72a³b⁴c⁵ by 8ab²c³

Questions · 105

12. Factorisation

1 1 1 1 1 1 1 2 2 2 2 2 2 2 3 3 3 3 3 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 3 4 4 4 4 4 4 5 5 5 5 6 7 1 1 1 1 1 2 2 2 2 2 2 2 3 3 3 3 3 3 4 4 4 4 4 4 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1