Divide the given polynomial by the given monomial

(3p³– 9p²q - 6pq²) ÷ (–3p)

In the given term

Dividend = (3p³– 9p²q - 6pq²)

Take out the common part in binomial term

= (3 × p × p × p– 3 × 3 × p × p × q - 2 × 3 × p × q × q )

= 3 × p(p²– 3pq - 2q²)

Divisor = (–3p)

=

= (-1) (p²– 3pq - 2q²)

= (2q² + 3pq - p²)

Hence dividing (3p³– 9p²q - 6pq²) by (–3p) gives out (2q² + 3pq - p²)