Divide the given polynomial by the given monomial

( a²b²c² + ab²c²) ÷abc

In the given term

Dividend = ( a²b²c² + ab²c²)

Take out the common part in binomial term

= ( × a × a × b × b × c × c + × 2 × a × b × b × c × c )

= × a × b × b × c × c (a + 2)

= ab _�²c²(a + 2)

Divisor = abc

=

=

= bc(a + 2)

Hence dividing ( a²b²c² + ab²c²) by abc gives out bc(a + 2)